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Find the midpoint of the line segment with end coordinates of:
(-2,-4) and (-1,-5)

Sagot :

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's use section formula ~

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{mx_2 + nx_1}{m + n} [/tex]

[tex]\qquad \sf  \dashrightarrow \:y = \dfrac{my_2 + ny_1}{m + n} [/tex]

And since mid point divides a line segment Into two equal parts, m : n = 1 : 1

so, take m = n = 1

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{(1 \times - 1)+(1 \times - 2)}{ 1+ 1} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{- 1- 2}{ 2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = \dfrac{ - 3}{ 2} [/tex]

Now, let's find y - coordinate ~

[tex]\qquad \sf  \dashrightarrow \:y = \dfrac{(1 \times - 5) + (1 \times - 4)}{1 + 1} [/tex]

[tex]\qquad \sf  \dashrightarrow \:y = \dfrac{ - 5 - 4}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:y = \dfrac{ - 9}{2} [/tex]

So, coordinates of midpoint is ~

[tex]\qquad \sf  \dashrightarrow \:( - \dfrac{3}{2} ,- \dfrac{9}{2} )[/tex]