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What is the equation of the line that passes through the point (- 2, - 1) and has a slope of 5/2

Sagot :

Answer:

[tex]equation \: of \: a \: line \\ y - y1 = m(x - x1) \\ y - ( - 1) = \frac{5}{2}(x - ( - 2)) \\ 2(y + 1 )= 5(x + 2) \\ 2y + 2 = 5x + 10 \\ 2y - 5x - 8 = 0[/tex]

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