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If a gas has a volume of 1.25 l at a temperature of 300 k, what will the volume change to if the container is cooled to 200k

Sagot :

Eduard22sly

The volume of the gas when the container is cooled from a temperature of 300 K to 200 K is 0.83 L

Charles' law

Charles' law states as follow:

V₁ / T₁ = V₂ / T₂

Where

  • V₁ is the initial volume
  • T₁ is the initial temperature
  • V₂ is the new volume
  • T₂ is the new temperature

How to determine the new volume

From the question given above, the following data were obtained

  • Initial volume (V₁) = 1.25 L
  • Initial temperature (T₁) = 300 K
  • New temperature (T₂) = 200 K
  • New Volume (V₂) =?

V₁ / T₁ = V₂ / T₂

1.25 / 300 = V₂ / 200

Cross multiply

300 × V₂ = 1.25 × 200

Divide both side by 300

V₂ = (1.25 × 200) / 300

V₂ = 0.83 L

Learn more about gas laws:

https://brainly.com/question/6844441

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