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The length of a rectangle is eight more than triple the width. If the perimeter is 168 inches, find the dimensions.

Sagot :

aj0347291

Answer:

P= 2(3W + 7) + 2(W) = 110.

                         P= 6W + 14 + 2W = 110.

                           = 8W + 14 = 110.

                           = 8W = 110 - 14 = 96

                                 W = 96/8 = 12- inches.

Now solve for (L) by L = 3W + 7 = 3(12) + 7 = 36 + 7 = 43- inches

7=43 inches if this help.can u mark me brainliest

shubhamchouhanvrVT

The width of the rectangle is 12 inches and the length is 43 inches.

What is the perimeter?

The perimeter is defined as the sum of all the sides of the figure. It is given that the length of a rectangle is eight more than triple the width and the perimeter is 168 inches.

The length and the width are calculated as:-

P= 2(3W + 7) + 2(W) = 110.

6W + 14 + 2W = 110.

8W + 14 = 110.

8W = 110 - 14 = 96

W = 96/8 = 12 inches.

Now solve for (L) by

L = 3W + 7 = 3(12) + 7

L = 36 + 7 = 43 inches

Hence, the width is 12 inches and the length is 43 inches.

To know more about perimeter follow

https://brainly.com/question/19819849

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