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Sagot :
[tex] 4(2x+3)=2(3x-4)\\
8x+12=6x-8\\
2x=-20\\
x=-10 \Rightarrow A[/tex]
A. One Solution.
If you distribute the 4 and 2 you're left with
8x+12=6x-8
+8 to both sides
8x+20=6x
-8x both sides
20=-2x
Divide by -2
X=-10
If you distribute the 4 and 2 you're left with
8x+12=6x-8
+8 to both sides
8x+20=6x
-8x both sides
20=-2x
Divide by -2
X=-10
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