Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

A 20.0-ml sample of a 0.200 mhbr solution is titrated with a 0.200 mnaoh solution. calculate the ph of the solution after the following volumes of base have been added.

Sagot :

ogorwyne

The calculated pH of the solutions are given below:

  • The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
  • The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
  • The pH of the solution after 20.0 ml of base is added to it is calculated as 7.

What is pH?

This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.

HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.

Mol of HBr = Mol * Vol

= 0.200 * 20mL

= 4 mmol

A. Moles of NaOH added

= 0.2 X 14

= 2.8 mmol

Moles of H+ that did not react

= 4 - 2.8

= 1.2 mmol

1.2/1000 = 0.0012 moles

Total volume = 20 + 14

= 34 mL to litres

= 0.034 L

Molarity of H+ = 0.0012 / 0.034L

= 0.035 M

-log[0.035] = 1.45

The pH of the solution is  1.45

B. NaOH added = 19.8 * 0.2 =

3.96 mmoles

The unreacted solution

= 4.0 - 3.96

= 0.04 mmol

0.04/1000 = 0.00004 moles

Total volume = 20 + 19.8

= 39.8mL

Converted to litres = 0.0398L

Molarity  = 0.00004 / 0.0398L

= 0.001

-log(0.001) = 3.0

The ph Is therefore 3.0

C. Moles of NaOH added = 0.2*20mL = 4mmol

All the H+ are going to be consumed here. This would result into a neutral solution pH = 7

Complete question:

20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.

A. 14.0 mL

B. 19.8 mL

C. 20.0 mL

Read more on pH here; https://brainly.com/question/22390063

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.