From the calcuation, the concentration of the copper II ion is 0.98 M.
What is an electrochemical cell?
An electrochemical cell is one in which current is produced by means of a chemical reaction. In this cell, the cell reaction is;
Cd(s) + Cu^2+(aq) ----> Cd^2+(aq) + Cu(s)
E°cell = 0.34 V - (-0.40V) = 0.74 V
Using the Nernst equation;
0.775= 0.74 - 0.0592/2 log(6.5 × 10-2)/[Cu^2+]
0.775 - 0.74 = - 0.0592/2 log(6.5 × 10-2)/[Cu^2+]
0.035 = -0.0296 log(6.5 × 10-2)/[Cu^2+]
0.035 /-0.0296 = log(6.5 × 10-2)/[Cu^2+]
-1.18 = log(6.5 × 10-2)/[Cu^2+]
Antilog (-1.18) = (6.5 × 10-2)/[Cu^2+]
0.066= (6.5 × 10-2)/[Cu^2+]
[Cu^2+] = (6.5 × 10-2)/0.066
[Cu^2+] =0.98 M
Learn more about Nernst equation: https://brainly.com/question/22724431
