jaylab2726
Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A foil boat measures 4.0cm by 5.0cm and has a mass of 100.0g. If you put the boat in water, how far will it sink? (Recall the density of water is 1.0 g/mL) (answer with a number; units are cm)

Sagot :

zahraayassera

Answer:

Let the volume of the block of wood be

V

c

m

3

and its density be

d

w

g

c

m

−

3

So the weight of the block

=

V

d

w

g

dyne, where g is the acceleration due to gravity

=

980

c

m

s

−

2

The block floats in liquid of density

0.8

g

c

m

−

3

with

1

4

t

h

of its volume submerged.So the upward buoyant force acting on the block is the weight of displaced liquid

=

1

4

V

×

0.8

×

g

dyne.

Hence by cindition of floatation

V

×

d

w

×

g

=

1

4

×

V

×

0.8

×

g

⇒

d

w

=

0.2

g

c

m

-3

,

Now let the density of oil be

d

o

g

c

m

-3

The block floats in oil with 60% of its volume submerged.So the buoyant force balancing the weight of the block is the weight of displaced oil =

60

%

×

V

×

d

o

×

g

dyne

Now applying the condition of floatation we get

60

%

×

V

×

d

o

×

g

=

V

×

d

w

×

g

⇒

60

100

×

V

×

d

o

×

g

=

V

×

0.2

×

g

⇒

d

o

=

0.2

×

10

6

=

1

3

=

0.33

g

c

m

−

3

Explanation:

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.