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Makayla leans a 26-foot ladder against a wall so that it forms an angle of 69^{\circ} ∘ with the ground. What’s the horizontal distance between the base of the ladder and the wall? Round your answer to the nearest tenth of a foot if necessary.

Sagot :

The base of the ladder and the wall forms a right triangle

The horizontal distance between the base of the ladder and the wall is 9.3 feet

How to determine the horizontal distance?

The given parametes are:

Angle = 69 degrees

Length of the ladder (l) = 26 feet

The horizontal distance (h) is calculated using the following cosine ratio

cos(θ) = h/l

Substitute known values

cos(69) = h/26

Make h the subject

h = 26 * cos(69)

Evaluate the product

h = 9.3

Hence, the horizontal distance between the base of the ladder and the wall is 9.3 feet

Read more about right triangles at:

https://brainly.com/question/2437195

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