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Sagot :
Since [tex]|z| = 1.301 \leq z_1 = 1.64[/tex] null hypothesis on this data is not rejected.
Null and Alternative Hypothesis
Data;
- sample mean x1 = 240993
- population standard deviation σ1 = 25875
- sample size n1 = 35
- sample mean x2 = 249237
- population standard mean σ2 = 27110
- sample size n2 = 35
- significance level α = 0.10
H_o = μ1 = μ2
H_o = μ1 ≠ μ2
This is a two-tailed test and population standard deviation will be used.
Test Statistic
The z-stat is
[tex]z = \frac{x_1 - x_2}{\sqrt{\frac{\sigma_1^2}{n_1}+ \frac{\sigma_1 ^2}{n_2} } } \\z=\frac{240993-249237}{\sqrt{\frac{25875^2}{35}+ \frac{27110^2}{35} } } \\z = \frac{-8244}{6334.6388} \\z = -1.301[/tex]
The significance level is α = 0.1 and the critical value for a two-tailed test is
[tex]Z_t = Z_1 - _\alpha _/_2 = 1.64[/tex]
Since [tex]|z| = 1.301 \leq z_1 = 1.64[/tex], we can assume that the null hypothesis is not rejected.
Learn more on null hypothesis here;
https://brainly.com/question/15980493
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