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Give the dimensions of 2 solids with equal surface area and different volume

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Two solids with the same surface and different volumes are a cube of side length of 1 unit, and a sphere of radius of 0.69 units.

How to find the two solids?

First, let's define a cube of a side length of 1 unit. The surface of this cube is equal to 6 times the area of one of the faces, or:

S  = 6*(1 unit square) = 6 units square.

And the volume is equal to the side length cubed, so we have:

V = (1 unit)^3 = 1 unit cubed.

Now, let's find a sphere with the same surface than our cube. For a sphere of radius R, the surface is:

S = 4*3.14*R^2

Then we must have:

4*3.14*R^2 = 6 units square

R = √(6/(4*3.14)) units = 0.69 units.

And the volume of this sphere is:

V = (4/3)*3.14*R^3 = (4/3)*3.14*(0.69 units)^3 = 1.38 cubic units.

So the sphere has the same surface and more volume.

If you want to learn more about solids, you can read:

https://brainly.com/question/10171109

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