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11. As early as 1938. the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the following (unbalanced) reaction: NaOH +CO2-
Na2CO3 + H2O.
a. If the average human body discharges 925,0 g CO, per day, how many moles of NaOH are
needed each day for each person in the spacecraft?
b. How many moles of each product are formed?

Sagot :

okpalawalter8

For a (unbalanced) reaction: NaOH +CO2-Na2CO3 + H2O, the moles of NaOH and moles of each product are formed are mathematically given as

a) Moles of NaOH =44.05

b)   Moles of Na2CO3=21.0

  • Moles of H2O= 21.0

What is the moles of NaOH and what moles of each product are formed?

Generally, the equation for the Chemical reaction  is mathematically given as

2 NaOH(aq)+ CO2(g)------> Na2CO3(aq)+ H2O(l)

Therefore

Moles of CO2= 925/44

Moles of CO2=21.0

Hence

Moles of NaOH = 2 x Moles of CO2

Moles of NaOH = 2x925/44

Moles of NaOH =44.05

In conclusion

Moles of Na2CO3 925/44

Moles of Na2CO3=21.0

And

Moles of H2O= 925/44

Moles of H2O= 21.0

Read more about Chemical reaction

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