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2=x^2-10x solve by completing the square

Sagot :

loneguy

[tex]2=x^2-10x\\\\\implies x^2 -10x =2\\\\\implies x^2 -2\cdot 5 x +5^2 -5^2 = 2\\\\\implies x^2 -2\cdot 5x +5^2 = 2+5^2 \\\\\implies (x-5)^2 = 27\\\\\implies x-5 = \pm\sqrt {27}\\\\\implies x = \pm\sqrt{27} +5=\pm3\sqrt{3}+5\\\\\text{Hence,}~ x = 5+3\sqrt 3~\text{or}~ x = 5-3\sqrt 3[/tex]

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