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Sagot :
Answer:
x = 3 ± 2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
x² - 6x + 1 = 0 ( subtract 1 from both sides )
x² - 6x = - 1
to complete the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = - 1 + 9
(x - 3)² = 8 ( take square root of both sides )
x - 3 = ± [tex]\sqrt{8}[/tex] = ± 2[tex]\sqrt{2}[/tex] ( add 3 to both sides )
x = 3 ± 2[tex]\sqrt{2}[/tex]
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