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At a basketball game, a vendor sold a combined total of 197 sodas and hot dogs. The number of hot dogs sold was 41 less than the number of sodas sold. Find the number of sodas sold and the number of hot dogs sold.

The number of sodas sold: ?
The number of hot dogs sold: ?

Sagot :

TheAmethyst

Question : -

At a basketball game, a vendor sold a combined total of 197 sodas and hot dogs. The number of hot dogs sold was 41 less than the number of sodas sold. Find the number of sodas sold and the number of hot dogs sold .

Given : -

  • Total of sodas and hot dog sold = 197

  • No. of hot dogs sold = 41 less than the no. of sodas sold

To Find : -

  • No. of soda sold

  • No. of hot dog sold

Concept : -

We have to solve this question by making equation and after creating equations we have to solve them properly to get the final answer .

To Assume : -

  • Let the no. of soda sold be x .

  • Let the no. of hot dogs sold be x - 41 ( Because they are 41 less than sodas )

So Starting Solution : -

According to question we know that combined total of sodas and hot dogs is :

  • x + ( x - 41 ) = 197

  • x + x - 41 = 197

  • 2x - 41 = 197

  • 2x = 197 + 41

  • 2x = 238

  • x = 238/2

  • x = 119

Therefore , No. of sodas sold is 119 .

Now , Hot dogs :

  • x - 41

  • 119 - 41

  • 78

Therefore , No. of hot dogs sold is 78 .

Verifying :

We know that their combined sum is equal to 197 . So ,

  • Sodas + Hot Dogs = 197

  • 119 + 78 = 197

  • 197 = 197

  • L.H.S = R.H.S

Therefore , our answer is valid .

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