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Sagot :
Answer:
∠EHF = 132°
Step-by-step explanation:
Both angles lie on a straight line.
=====================
- ∠EHF + ∠FHG = 180°
- 2(x) + 48° = 180°
- 2(x) = 180° - 48°
- 2(x) = 132°
- x = 66°
Then ∠EHF :
- 2(x)
- 2(66)
- 132°
Angles are supplementary hence their sum is 180°
So
- 2x+48=180
- 2x=180-48
- 2x=132
- x=66
So
<EHF=2(66)=132°
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