Answer:
A, D
Step-by-step explanation:
Given function: [tex]f(x)=x^2+4x-3[/tex]
Axis of symmetry
[tex]\textsf{Axis of Symmetry formula : }x=-\dfrac{b}{2a}[/tex]
for a quadratic equation in standard form [tex]y=ax^2+bx+c[/tex]
[tex]\implies \textsf{Axis of symmetry}: x=-\dfrac{4}{2}=-2[/tex]
Maximum/Minimum point (vertex)
The max/min point is the turning point of the parabola.
The x-value of the turning point is the axis of symmetry.
[tex]\implies \textsf{Turning point}:f(-2)=(-2)^2+4(-2)-3=-7[/tex]
Turning point (vertex) = (-2, -7)
As the leading coefficient is positive, the parabola opens upwards. Therefore, the turning point (-2, -7) will be a minimum.
Domain & Range
Domain: input values → All real numbers
Range: output values → [tex]x\geq -7[/tex] [as (-2, -7) is the minimum point]
End behavior
As the leading degree is positive and the leading coefficient is positive:
[tex]f(x) \rightarrow + \infty, \textsf{ as } x \rightarrow - \infty[/tex]
[tex]f(x) \rightarrow + \infty, \textsf{ as } x \rightarrow + \infty[/tex]
