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Oxygen gas occupies a volume of 95 ml at 305 k. what volume will it occupy at 550 k?

Sagot :

nuhulawal20

The new volume of the oxgen gas as the temperature is increased is 171.3ml.

Given the data in the question;

  • Initial olume of oxygen gas; [tex]V_1 = 95ml = 0.095L[/tex]
  • Intial temperature; [tex]T_1 = 305K[/tex]
  • Final temperature; [tex]T_2 = 550K[/tex]
  • Final volume of oxygen gas; [tex]V_2 = \ ?[/tex]

Charles's law

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

To determine the new volume of the oxgen gas as the temperature is increased, we substitute our given values into the expression above.

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}\\ \\ \frac{0.095L}{305K} = \frac{V_2}{550K}\\\\V_2 * 305K = 0.095L * 550K\\\\V_2 * 305K = 52.25LK\\\\V_2 = \frac{52.25LK}{305K} \\\\V_2 = 0.1713L\\\\V_2 = 171.3ml[/tex]

Therefore, the new volume of the oxgen gas as the temperature is increased is 171.3ml.

Learn more about Charles's law here: brainly.com/question/12835309

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