Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Oxygen gas occupies a volume of 95 ml at 305 k. what volume will it occupy at 550 k?

Sagot :

nuhulawal20

The new volume of the oxgen gas as the temperature is increased is 171.3ml.

Given the data in the question;

  • Initial olume of oxygen gas; [tex]V_1 = 95ml = 0.095L[/tex]
  • Intial temperature; [tex]T_1 = 305K[/tex]
  • Final temperature; [tex]T_2 = 550K[/tex]
  • Final volume of oxygen gas; [tex]V_2 = \ ?[/tex]

Charles's law

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

To determine the new volume of the oxgen gas as the temperature is increased, we substitute our given values into the expression above.

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}\\ \\ \frac{0.095L}{305K} = \frac{V_2}{550K}\\\\V_2 * 305K = 0.095L * 550K\\\\V_2 * 305K = 52.25LK\\\\V_2 = \frac{52.25LK}{305K} \\\\V_2 = 0.1713L\\\\V_2 = 171.3ml[/tex]

Therefore, the new volume of the oxgen gas as the temperature is increased is 171.3ml.

Learn more about Charles's law here: brainly.com/question/12835309

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.