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Consider the following incomplete deposit ticket: a deposit ticket. the amounts deposited were 491 dollars and 60 cents and 157 dollars and 68 cents. 68 dollars and 44 cents was taken out as cash. the total on the ticket is 686 dollars and 4 cents. what was the value of the third check tony deposited? a. $617.60 b. $105.20 c. $31.28 d. $36.76

Sagot :

Tony deposited three checks as given in deposite ticket. The amount of the third check that Tony deposited is given by: Option B: $105.20

How to get the resultant deposited amount?

Resultant deposited amount = Deposited amount - The amount deducted.

We subtract the amount deducted from the amount deposited to get the resultant deposite amount that will go in bank.

Well, it might be that we deduced more than what we deposite, in that case net deposite will come as negative, indicating that there is deduction instead of deposite.

The missing image of the deposite ticket is attached below.

From that image, we can see that:

  • Deposited amounts were:  
  1.    First check: $491.60
  2.    Second check: $157.68
  3.    Third check: $x (to find)
  • Deducted amount was:  $68.44
  • Net deposite = $686.04

Thus, the net deposited amount is:

Net deposite = deposited amounts - deduced amounts

686.04 = 491.6 + 157.68 + x - 68.44 (all in dollars)

[tex]686.04 = x+ 491.6 + 157.68 - 68.44\\686.04 = x + 580.84\\\\\text{Subtracting 580.04 from both the sides} \\\\686.04 - 580.84 = x\\x = 105.20 \: \rm dollars[/tex]

Net deposite = 105.20 (in dollars).

Thus, the amount of the third check that Tony deposited is given by: Option B: $105.20

Learn more about total deposite here:

https://brainly.com/question/27244866

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