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A sample of gas has a volume of 8.20 L at 0.750 atm and 375 K. What volume (in L) does the gas occupy at 817 torr and 325 K?

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nuhulawal20

The new volume occupied by the sample of gas is 4.96L.

Given the data in the question;

  • Initila pressure; [tex]P_1 = 0.750atm[/tex]
  • Final pressure; [tex]P_2 = 817torr = 1.075atm[/tex]
  • Inital temperature; [tex]T_1 = 375K[/tex]
  • Final temperature; [tex]T_2 = 325K[/tex]
  • Initial Volume; [tex]V_1 = 8.20L[/tex]

Final Volume; [tex]V_2 = \ ?[/tex]

Combined gas law

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]

To calculate the new volume the gas occupy, we subtsitute our given values into the expression above.

[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\\ \\ P_1V_1T_2 = P_2V_2T_1\\\\0.750atm * 8.20L * 325K = 1.075atm * V_2 * 375K\\\\1998.75LatmK = 403.125atmK * V_2\\\\V_2 = \frac{1998.75LatmK}{403.125atmK} \\\\V_2 = 4.96L[/tex]

Therefore, the new volume occupied by the sample of gas is 4.96L.

Learn more about the combined gas law: brainly.com/question/25944795

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