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Human blood is divided into 8 possible blood types. The rarest blood type is AB negative. Only 1% of the population has this blood type. Suppose a random sample of 50 people is selected. Can we find the probability that more than 3% of the sample has AB negative blood

Sagot :

Using the normal approximation to the binomial distribution, it is found since np = 0.5 < 10, we cannot find the probability.

Normal Probability Distribution

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with [tex]\mu = np, \sigma = \sqrt{np(1-p)}[/tex], as long as [tex]np \geq 10, n(1 - p) \geq 10[/tex].

In this problem, we have that:

  • Only 1% of the population has this blood type, hence p = 0.01.
  • A random sample of 50 people is selected, hence n = 50.

Then:

np = 50 x 0.01 = 0.5 < 10.

Thus we cannot find the probability.

More can be learned about the normal approximation to the binomial distribution at https://brainly.com/question/14424710