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Sagot :
#b
[tex]\\ \rm\rightarrowtail tan47=\dfrac{b}{21}[/tex]
[tex]\\ \rm\rightarrowtail b=21tan47[/tex]
[tex]\\ \rm\rightarrowtail b=22.5[/tex]
#c
[tex]\\ \rm\rightarrowtail cos47=\dfrac{21}{c}[/tex]
[tex]\\ \rm\rightarrowtail c=21/cos47[/tex]
[tex]\\ \rm\rightarrowtail c=30.88[/tex]
Answer:
c = 30.8 (nearest tenth)
Step-by-step explanation:
Pythagoras' Theorem: a² + b² = c²
(where a and b are the legs, and c is the hypotenuse, of a right triangle)
Given:
- a = 21
- b = 22.5
Substitute given values into the formula and solve for c:
⇒ 21² + 22.5² = c²
⇒ 947.25 = c²
⇒ c = ±√(947.25)
⇒ c = ±30.8 (nearest tenth)
As distance is positive, c = 30.8 (nearest tenth) only
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