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The concentration of A is initially 0.150 M before it proceeds to equilibrium. The system is at 298 K. What is the equilibrium concentration of B

Sagot :

okpalawalter8

For a  concentration of  is initially 0.150 M before it proceeds to equilibrium, the equilibrium concentration of B  is mathematically given as

x=3.0*10^{-7}m

What is the equilibrium concentration of B?

Generally, the equation for the  change in Gibbs free energy   is mathematically given as

dG=-RTInK

Therefore

31.5*10*^{3}=-(8.314)(298)(ink)

K=3*10^(-6)

Eqution

A--->B

K=x/0.1-x

x=3.0*10^{-7}m

In conclusion, the equilibrium concentration

x=3.0*10^{-7}m

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