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Evaluate the frequency of the third harmonies of a
closed pipe of length 0.3m. (speed of sound in air
= 340ms]


Sagot :

The frequency of the third harmonics of the closed pipe is 850 Hz.

Third harmonics frequency

The frequency of the third harmonics or second overtone is determined as follows;

Wavelength, λ = 4L/3

Frequency, F = v/λ

[tex]F_3 = \frac{3v}{4L}[/tex]

Where;

  • v is the velocity of sound in air = 340 m/s
  • L is length of the pipe = 0.3 m

Substitute the given parameters and solve for the frequency

F₃ = (3 x 340)/(4 x 0.3)

F₃ = 850 Hz

Thus, the frequency of the third harmonics of the closed pipe is 850 Hz.

Learn more about third harmonics here: https://brainly.com/question/4290297

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