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What is the molarity of a solution that contains 30. grams of naoh in 500. milliliters of solution?.

Sagot :

ganjilaya2019

Answer:

1.5 mol/L

Explanation:

molarity = moles/litres

NaOH = 23 + 16 + 1 = 40 g/mol

[tex] ? \: mol \: naoh \: = 30 \: g \: naoh \: \times \\ \\ \frac{1 \: mol \: naoh}{40 \: g \: naoh} = 0.75 \: mol \: naoh[/tex]

molarity = 0.75 mol NaOH ÷ 0.5 L = 1.5 mol/L NaOH

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