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Sagot :
The Neptune's time period of orbit is 164.3 earth years.
We have given that the mass of the sun is 2 × 1030 kg.
The distance between neptune and the sun is 30 au
What is the mathematical expression of Kepler's law ?
[tex]T^2 = 4\pi ^2a^3/GM[/tex]
Where T is in earth years, a is astronomical units and
M = solar masses.
4π²/GM = 1,
Therefore we get
[tex]T^2 = a^3[/tex]
[tex]T = \sqrt(a^3)[/tex]
[tex]T = \sqrt(30^3)[/tex]
[tex]T = 164.3[/tex]
Therefore, the Neptune's time period of orbit is 164.3 earth years.
To learn more about the time period visit:
https://brainly.com/question/329317
Answer:
b. 164 earth years
Step-by-step explanation:
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