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Sagot :
Answer:
So, we can check step by step.
2x^2-7x+5=0
So, 2x^2-2x-5x+5=0 is correct
2x(x-1)=2x^2-2x, 5(x-1)=-5x + 5= 0, that step is correct
(I'll skip the next step)
2x-5=0,
2x=5
x=5/2, NOT 2/5
The other one is correct
Sorry if this seems a bit vague!
[tex]\\ \rm\Rrightarrow 2x^2-7x+5=0[/tex]
- Split the middle term
[tex]\\ \rm\Rrightarrow 2x^2-2x-5x+5=0[/tex]
- Take common
[tex]\\ \rm\Rrightarrow 2x(x-1)-5(x-1)=0[/tex]
- Factor up
[tex]\\ \rm\Rrightarrow (2x-5)(x-1)=0[/tex]
- Find x
[tex]\\ \rm\Rrightarrow x=5/2,1[/tex]
Lauren written 2/5 instead of 5/2
Let's verify once more
- 2x-5=0
- 2x=5
- x=5/2
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