Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
The difference between the maximum value of g(x) and the minimum value of f(x) is 5.
Given function is:
[tex]f(x)=x^{2} -2x+8[/tex]......(1)
What is the general form of a quadratic equation?
The general form of a quadratic equation is [tex]ax^{2} +bx+c=0[/tex] with [tex]a\neq 0[/tex].
As we know the minimum value of a quadratic function is [tex]\frac{4ac-b^{2} }{4a}[/tex] when a>0
For f(x) a>0 so minimum value of f(x) = [tex]\frac{4*1*8-(-2)^2}{4*1}[/tex]=7
From the graph, the maximum value of g(x) =12
So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5
Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.
To get more about quadratic functions visit:
https://brainly.com/question/1214333
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.