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In exercises 3–6, find an explicit description of nul a by listing vectors that span the null space.

Sagot :

The explicit description of null A by listing vectors that span the null space.

[tex]\left[\begin{array}{ccc}{7} &&&{-4} \\{1} \\{0} \end{array}\right] \left[\begin{array}{ccc}{-6} &&&{2} \\{0} \\{1} \end{array}\right][/tex]

What is the Matrix Vector?

We are given the matrix vector;

[1  3 5 0]

[0 1 4 -2]

Now, let's find the general Ax = 0 solution for the free variables. Thus;

[A, 0] =  

[1 3 5  0]

[0 1 4 -2]

Thus;

R₁ → R₁ - 3R₂

⇒ [1 0 -7  6 0]

   [0 1 4  -2 0]

The general solution is:

x₁ = 7x₃ - 6x₄

x₂ = -4x₃ + 2x₄

x₃ and x₄ are free variables

x = [tex]\left[\begin{array}{ccc}x_{1} &&&x_{2} \\x_{3} \\x_{4} \end{array}\right][/tex] = [tex]x_{3} \left[\begin{array}{ccc}{7} &&&{-4} \\{1} \\{0} \end{array}\right] + x_{4} \left[\begin{array}{ccc}{-6} &&&{2} \\{0} \\{1} \end{array}\right][/tex]

Thus, Null A is;

[tex]\left[\begin{array}{ccc}{7} &&&{-4} \\{1} \\{0} \end{array}\right] \left[\begin{array}{ccc}{-6} &&&{2} \\{0} \\{1} \end{array}\right][/tex]

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