Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

The perimeter of arectangular poultry farm is 38 meter . if 3 meter subtracted from its length and 2 meter from its breadth , the length will be two times the breadth .find the area of the farm

Sagot :

sqdancefan

Answer:

  82 2/9 square meters

Step-by-step explanation:

The problem statement gives us two relations between length and width. We can write those using equations and the variables L and W for length and widh, in meters.

  P = 2(L +W) . . . . . . formula for the perimeter of a rectangle

  38 = 2(L +W) . . . . . the perimeter is 38 meters

  (L -3) = 2(W -2) . . . . length less 3 is twice the difference of wdith and 2.

__

Dividing the first equation by 2 gives ...

  19 = L +W

Solving this for L gives ...

  L = 19 -W

Substituting for L in the second equation, we have ...

  (19 -W) -3 = 2(W -2)

  16 -W = 2W -4 . . . . . . . simplify

  20 = 3W . . . . . . . . . . . add W+4

  W = 20/3 . . . . . . . . . divide by 3

  L = 19 -20/3 = 37/3 . . . . find L from W

__

The area of the farm is the product of length and width:

  A = LW = (37/3 m)(20/3 m) = 740/9 m²

  A = 82 2/9 m²

The area of the farm is 82 2/9 square meters.

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.