Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Write a program that allows two players (player X and player O) to play a game of tic-tac-toe. Use a two- dimensional char array with three rows and three columns as the game board. Each element of the array should be initialized with an asterisk (*). The players take turns making moves and the program keeps track of whose turn it is. Player X moves first. The program should run a loop that:

Sagot :

#include <iostream>

using namespace std;

//function prototypes

void showBoard(char[][3]);

bool checkWinner(char[][3], char);

void playerMove(char[][3], char);

int main()

{

  //declare variables needed

  //declare 2D array for the board

  //and initialize with all *

  char board[3][3] = {{'*', '*', '*'},

                      {'*', '*', '*'},

                      {'*', '*', '*'}};

  int moves = 0;  //variable to keep track

                  //of number of moves

                  //to determine tie

  cout << "TIC - TAC - TOE\n\n";

  //while loop to repeat until 9 moves are done

  while(true){

      //display board

      showBoard(board);

      cout << "Player 1 moves\n";

      //get player X move

      playerMove(board, 'X');

      //increment moves counter

      moves++;

      //if this is a winning move

      //store winner and terminate

      if(checkWinner(board, 'X')){

          showBoard(board);

          cout << "\nPlayer 1 (X) wins!\n";

          return 0;

      }

      //if 9 moves are done

      //break from loop

      if(moves == 9)

          break;

      //display board again

      showBoard(board);

      cout << "Player 2 moves\n";

      //do the same thing for player O

      playerMove(board, 'O');

      moves++;

      if(checkWinner(board, 'O')){

          showBoard(board);

          cout << "\nPlayer 2 (O) wins!\n";

          return 0;

      }

  }

  //if we have gone this far and program

  //still has not terminated (no winner)

  //it means this is a tie

  showBoard(board);

  cout << "This game is a tie!\n";

  //return 0 to mark successful completion of program

  return 0;

}

//this function is helpful because we need to show

//the board repetitively during the program

void showBoard(char board[][3]){

  cout << endl;

  //loop on the rows

  for(int row = 0; row < 3; row++){

      //loop on the columns

      for(int col = 0; col < 3; col++)

          cout << board[row][col] << "    ";

      //display newline after each row

      cout << endl << endl;

  }

  cout << endl;

}

//this function checks if second argument

//is a winning player

bool checkWinner(char board[][3], char player){

  //boolean variable to check

  //for winner later

  bool flag;

  //CHECK FOR WINNER IN ROWS

  for(int row = 0; row < 3; row++){

      //initialize flag to true

      flag = true;

      //loop within a row

      for(int col = 0; col < 3; col++){

          //Notice that the right part of the

          //assignment operator, is an expression

          //with a relational operator (==)

          //this expression will yield either

          //true (1) or false (0)

          //while flag is already true (1)

          //if multiplied by true (1) will result

          //in true(0), or multiplied by false (0)

          //will result in false (0)

          flag *= (board[row][col] == player);

      }

      //after checking within row, if the flag

      //is still true at this point, it means we have

      //three chars of the same kind within the row,

      //thus we have a winner

      if(flag)

          return true;

      else

          continue;

  }

  //CHECK FOR WINNER IN COLUMNS

  //using a similar logic

  for(int col = 0; col < 3; col++){

      flag = true;

      for(int row = 0; row < 3; row++){

          flag *= (board[row][col] == player);

      }

      if(flag)

          return true;

      else

          continue;

  }

  //CHECK FIRST DIAGONAL (row = col)

  //reset flag to true

  flag = true;

  //check diagonal

  for(int i = 0; i < 3; i++){

      flag *= (board[i][i] == player);

  }

  //check if there is winner

  if(flag)

      return true;

  //CHECK OTHER DIAGONAL (row = 2 - col)

  //reset flag to true

  flag = true;

  //check diagonal

  for(int col = 0; col < 3; col++){

      flag *= (board[2-col][col] == player);

  }

  //check if there is winner

  if(flag)

      return true;

  //if all of these have been checked

  //and function still has not returned,

  //it means there is no winner

  return false;

}

//this function gets a move from the player,

//checks if it is valid, and if yes it puts

//it on the board

void playerMove(char board[][3], char player){

  //variables to store user move

  int row, col;

  //get user move

  cout << "Row: ";

  cin >> row;

  cout << "Col: ";

  cin >> col;

  //check if this is valid move

  //you have to check if that tile has

  //already been marked, or if tile

  //of choice is out of bounds of board

  while(board[row-1][col-1] != '*' ||

        row > 3 || row < 0 ||

        col > 3 || row < 0)

          {

      cout << "Invalid move! Try again\n";

      cout << "Row: ";

      cin >> row;

      cout << "Col: ";

      cin >> col;

  }

  //after validation, mark new move

  board[row-1][col-1] = player;

}

Answer:

if on edgen. The answer is c

Explanation:

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.