At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
The vertex of the graph is:
- the minimum point for a parabola that opens upwards
- the maximum point for a parabola that opens downwards
As this parabola opens upwards, the vertex is the minimum point.
From inspection of the graph, vertex = (-3, -1)
Equation of the graph
From inspection we can see that the x-intercepts are when
x = -4 and x = -2
[tex]\sf x = -4 \implies x+4=0[/tex]
[tex]\sf x = -2 \implies x+2=0[/tex]
Therefore:
[tex]\sf y=(x+4)(x+2)[/tex]
Expand:
[tex]\sf \implies y=x^2+6x+8[/tex]
Answer:
[tex]B)f(x) = {x}^{2} + 6x + 8[/tex]
Step-by-step explanation:
Let [tex] f(x)=x^2[/tex] be the parent function. With transformation of function, firstly,we know that,
- We can move it up or down by adding a constant to the y-value
algebraically
- g(x)=x²+C
Clearly, The parabola is moved down by 1 unit thus, C is -1. Therefore our function transforms to
- f(x)=x²-1
secondly, we know that,
- We can move it left or right by adding a constant to the x-value
algebraically,
- g(x)=(x+C)²
in case,
- C is positive, g(x) moves to the left and vise versa
Since the parabola is moved left by 3 unit, C is +3, and hence Our function eventually becomes
- [tex]f(x) = (x + 3 {)}^{2} - 1[/tex]
simplifying it yields:
[tex]\implies \boxed{f(x) = {x}^{2} + 6x + 8}[/tex]
Hence,B is our required answer
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.