cambriadaughty
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WILL GIVE BRAINLIEST The points Q(0,1), R(-9,-5), s(-7, -8), and T(2,-2) form rectangle QRST. Plot the points then click the "Graph Quadrilateral" button. Then find the area of the rectangle.​

WILL GIVE BRAINLIEST The Points Q01 R95 S7 8 And T22 Form Rectangle QRST Plot The Points Then Click The Graph Quadrilateral Button Then Find The Area Of The Rec class=

Sagot :

well, we know its a rectangle, so  hmmm opposite sides are not just parallel but equal, hmmm so the area of this rectangle we can get by Length * Width, in this case that'll be QT * TS

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Q(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad T(\stackrel{x_2}{2}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ QT=\sqrt{[2 - 0]^2 + [-2 - 1]^2}\implies QT=\sqrt{2^2 + (-3)^2}\implies QT=\sqrt{13} \\\\[-0.35em] ~\dotfill[/tex]

[tex]T(\stackrel{x_1}{2}~,~\stackrel{y_1}{-2})\qquad S(\stackrel{x_2}{-7}~,~\stackrel{y_2}{-8})~\hfill TS=\sqrt{[-7 - 2]^2 + [-8 - (-2)]^2} \\\\\\ TS=\sqrt{(-9)^2 + (-8+2)^2}\implies TS=\sqrt{117} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{\sqrt{13}\cdot \sqrt{117}\implies \sqrt{1521}\implies 39}[/tex]

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