At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
well, she put 130 bucks, and then she got back 132.6 after one year, so the interest earned is 132.6 - 130 = $2.6, thus
[tex]~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$2.60\\ P=\textit{original amount deposited}\dotfill & \$130\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &1 \end{cases} \\\\\\ 2.60 = (130)(\frac{r}{100})(1)\implies 2.6=\cfrac{130r}{100}\implies 260=130r \\\\\\ \cfrac{260}{130}=r\implies 2=r[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
