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Sagot :
Answer:
[tex]a_{n} =500(n) + 30,000[/tex]
Step-by-step explanation:
Hey there!
This equasion is correct because [tex]500[/tex] is being multiplied by the multiplyer which is [tex]n[/tex], how many years have gone by
After that The equasion adds [tex]30,000[/tex] because he started with [tex]30,000[/tex].
Answer:
The answer is [tex]a_{n} =500n+29,500.[/tex]
The recursive rule is [tex]a_{n} =a_{n-1} + 500[/tex]; [tex]a_{1}=30,000[/tex]. In other words, the nth term is the previous term + 500. The first term, as given, is a1 = 30,000.
Step-by-step explanation:
The answer is [tex]a_{n} =500n+29,500.[/tex]a_n = 500n + 29,500. It is easy to check: just plug in n = 1, and you'll get the first year's salary = 500•1 + 29,500 = 30,000.
Another way to find it is [tex]a_{n} =30,000+500(n-1)=30,000+500n-500=29,500+500n[/tex].
The recursive rule is [tex]a_{n} =a_{n-1} + 500[/tex]; [tex]a_{1}=30,000[/tex]. In other words, the nth term is the previous term + 500. The first term, as given, is [tex]a_{1}=30,000[/tex].
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