angeljaimon2
Answered

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Factor the polynomials completely, then solve. 4^2- 81 = 0​

Sagot :

Answer:

[tex]x=\pm\frac{9}{2}[/tex]

Step-by-step explanation:

I assume you mean [tex]4x^2-81=0[/tex]:

[tex]4x^2-81=0\\(2x-9)(2x+9)=0\\x=\frac{9}{2},\:x=-\frac{9}{2}\\x=\pm\frac{9}{2}[/tex]

We were able to work quickly here since the original left-side expression was a difference of squares.

Answer:

Step-by-step explanation:

4x^2 - 81 = 0

(2x - 9)(2x + 9) = 0

x = -9/2, 9/2

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