Answered

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What is the distance between points (8,3) and (53,31) on a coordinate plane?

Sagot :

Answer:

53 units

Step-by-step explanation:

Let [tex](x_1,y_1)\rightarrow(8,3)[/tex] and [tex](x_2,y_2)\rightarrow(53,31)[/tex] to use the distance formula:

[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(31-3)^2+(53-8)^2}\\\\d=\sqrt{(28)^2+(45)^2}\\\\d=\sqrt{784+2025}\\\\d=\sqrt{2809}\\\\d=53[/tex]

Thus, the distance between the two points is 53 units

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