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When three squares are joined at their vertices to form a right triangle, the combined area of the two smaller
squares is equal to the area of the largest square. Which three squares support this statement?
5 cm
3 cm

When Three Squares Are Joined At Their Vertices To Form A Right Triangle The Combined Area Of The Two Smaller Squares Is Equal To The Area Of The Largest Square class=

Sagot :

McCold

Answer:

Top right (one what has 16cm^2 and 9cm^2)

Step-by-step explanation:

The one in the top right and even though I cannot see what the area is of the biggest square, I can tell what it should be the two smaller squares combined

Hope this helps :)