Answered

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for the equation 3(2x - 5) = 6x + k which value of k will create an equation with infinitely many solutions?

a.) 15 b.) -5 c.) 5 d.) -15 Please show steps to solve this

Sagot :

naǫ
[tex]3(2x-5)=6x+k \\ 6x-15=6x+k \\ 6x-6x-15=k \\ -15=k \\ \boxed{k=-15} \Leftarrow D[/tex]
memecobb123

-15

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