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Sagot :
The equation for for perimeter of a rectangle is
2w + 2L = 154 meters
and we know that
w = .4L
so all we have to do is plug in what we know
2(.4L) + 2L = 154
.8L + 2L = 154
2.8L = 154
L = 55
now we know L we can solve for w with our first equation
2w + 2(55) = 154
2w = 44
w = 22
so the length is 55 and our width is 22.
Let check
55 *.4 = 22 so we are correct.
2w + 2L = 154 meters
and we know that
w = .4L
so all we have to do is plug in what we know
2(.4L) + 2L = 154
.8L + 2L = 154
2.8L = 154
L = 55
now we know L we can solve for w with our first equation
2w + 2(55) = 154
2w = 44
w = 22
so the length is 55 and our width is 22.
Let check
55 *.4 = 22 so we are correct.
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