Jamia23
Answered

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Solve the equation 3x^2+8x+5=0

Sagot :

[tex]3x^2+8x+5=0\\ 3x^2+3x+5x+5=0\\ 3x(x+1)+5(x+1)=0\\ (3x+5)(x+1)=0\\ x=-\dfrac{5}{3} \vee x=-1[/tex]
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