Answered

Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Points B and C lie on a circle with center O and radius r = 5 units. If the length of BC is 10.91 units, what is m∠BOC in radians? Use the value π = 3.1416, and round your answer to three decimal places.

Sagot :

AL2006

Seems to me that the situation described is impossible.

If the circle's radius is 5, then its diameter is 10. The diameter of the circle
is the farthest apart that two points on the circle can be.  So points 'B' and 'C'
can not be 10.91 apart.

==========================

Oh !  But wait.  I gues you mean the distance between them along the circle.
(You just said "the length of BC", which usually means the straight-line distance.)

OK. 
The piece of the circumference that's 10.91 long is (10.91/5) radiuses long.
So the central angle that encloses it is (10.91/5) = 2.182 radians.




boffeemadrid

Answer:

m∠BOC=2.182 radians

Step-by-step explanation:

It is given that Points B and C lie on a circle with center O and radius r = 5 units, length of BC=10.91 units, then using the formula,

[tex]S=r{\theta}[/tex] where S is the arc length, r is the radius and [tex]{\theta}[/tex] is in radians, thus

on substituting the values of S, r, we get

⇒[tex]10.91=(5){\theta}[/tex]

⇒[tex]{\theta}=\frac{10.91}{5}[/tex]

⇒[tex]{\theta}=2.182 radians[/tex]

Thus, m∠BOC=2.182 radians

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.