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what are four consecutive integers whose sum is 682

Sagot :

X+(x+1)+(x+2)+(x+3)=682.
4x+1+2+3=682
4x+6=682
4x=676
X=169

So it's 169, 170, 171, 172
naǫ
x, x+1, x+2, x+3 - four consecutive integers

[tex]x+x+1+x+2+x+3=682 \\ 4x+6=682 \ \ \ |-6 \\ 4x=676 \ \ \ |\div 4 \\ x=169 \\ \\ x+1=169+1=170 \\ x+2=169+2=171 \\ x+3=169+3=172[/tex]

The integers are 169, 170, 171 and 172.
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