Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

what are four consecutive integers whose sum is 682

Sagot :

X+(x+1)+(x+2)+(x+3)=682.
4x+1+2+3=682
4x+6=682
4x=676
X=169

So it's 169, 170, 171, 172
naǫ
x, x+1, x+2, x+3 - four consecutive integers

[tex]x+x+1+x+2+x+3=682 \\ 4x+6=682 \ \ \ |-6 \\ 4x=676 \ \ \ |\div 4 \\ x=169 \\ \\ x+1=169+1=170 \\ x+2=169+2=171 \\ x+3=169+3=172[/tex]

The integers are 169, 170, 171 and 172.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.