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what is an equation of the line that passes through the points (6,5) and (7,7)

Sagot :

Answer:

The slope of the line is m = 2.

The y-intercept is (0,7).

The equation of the line in the slope-intercept form is y = 2 x - 7.

Step-by-step explanation:

The slope of a line passing through two points [tex]P = \left(x_{1}, y_{1}\right)[/tex] and [tex]Q = \left(x_{2}, y_{2}\right)[/tex]

is given by  [tex]m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]

We have that [tex]x_{1} = 6[/tex] , [tex]y_{1} = 5y[/tex] , and [tex]y_{2} =7.[/tex]

Plug the given values into the formula for a slope: [tex]m=\frac{7-5}{7-6} =2[/tex].

Now, the y-intercept is [tex]b=y_{1} -mx_{1}[/tex] (or [tex]b =y_{2} -mx_{2}[/tex], the result is the same).

[tex]b=5-(2)*(6)=-7[/tex]

Finally, the equation of the line can be written in the form [tex]y=b+mx[/tex]:

[tex]y=2x-7[/tex]

Answer:

  • [tex]\Large\boxed{\sf{y=2x-7}}[/tex]

Step-by-step explanation:

The slope formula is used to find the equation of the line that passes through the points in this problem.

SLOPE FORMULA:

[tex]\Longrightarrow: \sf{\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{RISE}{RUN} }[/tex]

  • y₂=7
  • y₁=5
  • x₂=7
  • x₁=6

[tex]\Longrightarrow: \sf{\dfrac{7-5}{7-6}=\dfrac{2}{1}=2 }[/tex]

Use the slope-intercept form.

SLOPE-INTERCEPT FORM:

[tex]\Longrightarrow: \sf{Y=MX+B}[/tex]

[tex]\Longrightarrow: \text{The M represents the "slope".}[/tex]

[tex]\Longrightarrow: \text{The B represents the "y-intercept".}[/tex]

y=2x-7

  • Therefore, the slope is 2 and the y-intercept is 7.
  • The correct answer is y=2x-7.

I hope this helps. Let me know if you have any questions.