Answered

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15) A 12.0 g sample of helium gas occupies a volume of 12.6 L at a certain temperature and
pressure. What volume does a 24.0 g sample of neon occupy at these conditions of
temperature and pressure?

Sagot :

The required volume of sample of neon occupy at these conditions of temperature and pressure is 25.2L.

How do we convert grams into moles?

Mass (W) in grams of helium gas will be converted into moles (n) by using the below equation:

n = W/M, where

M = molar mass = 4g/mol

  • Initial moles of helium gas:

n = 12g / 4g/mol = 3 mol

  • Final moles of neon gas:

n = 24g / 4g/mol = 6 mol

And for this question as pressure and temperature for both the conditions is constant so ideal gas equation becomes:

V₁/n₁ = V₂/n₂, where

V₁ = initial volume = 12.6 L

n₁ = initial moles = 3 mol

V₂ = final volume = ?

n₂ = final moles = 6 mol

On putting these values, we get

V₂ = (12.6)(6) / (3) = 25.2 L

Hence required volume of neon gas is 25.2 L.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/3778152

#SPJ1

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