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Please Please Please help + show the work please! :)

Find the number of grams 9.30 x 10^-3 mole of SmO

Sagot :

Medunno13
The gram-formula mass of Sm is 150.36 u, and the gram-formula mass of O is 15.999 u, so the gram-formula mass of SmO is about 150.36+15.999 = 160.36 g/mol.

So, there are about (9.30 * 10^-3)(160.36)=1.49 grams

Molar mass of SmO or sodium methylate is 160g/mol

Now

  • No of moles =Given mass /Molar mass

Given mass

  • No of moles ×Molar mass
  • 9.3×10^{-3}×160
  • 1.488g
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