Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Hydrochloric acid is usually purchased in a concentrated form that is 37.0% HCl by mass and has a density of 1.20 g/mL. How much concentrated solution would it take to prepare 3.00 L of 0.480 M HCl upon dilution with water?

Sagot :

The required volume of concentrated stock solution of hydrochloric acid is 102.71 mL.

What is the relation between the volume & density?

Volume of any solution will be calculated by using the density as:

Volume = Mass/Density

Given that percent mass of HCl is 37%, so mass of the HCl = 37g

So that mass of solution = 100g

And density of solution = 1.2 g/mL

Volume of solution = 100/1.2 = 83.33 mL = 0.08333 L

Moles of HCl will be calculated as:

n = W/M, where

W = given mass = 37g

M = molar mass = 36.4g/mol

n = 37/36.4 = 1.014mol

Then the molarity of the stock solution will be calculated as:

M = n/V

M = 1.014 / 0.0833 = 12.17M

Now the required volume of stock solution will be calculated by using the following equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ is the molarity and volume of stock solution and M₂ & V₂ is the molarity and volume of dilute solution. On putting values in the above solution we get

12.17 × V₁ = 0.5 × 2500

12.17 × V₁ = 1250

V₁ = 102.71 mL

Hence required volume of stock solution is 102.71 mL.

To know more about molarity, visit the below link:
https://brainly.com/question/22283918

#SPJ1