Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The required volume of concentrated stock solution of hydrochloric acid is 102.71 mL.
What is the relation between the volume & density?
Volume of any solution will be calculated by using the density as:
Volume = Mass/Density
Given that percent mass of HCl is 37%, so mass of the HCl = 37g
So that mass of solution = 100g
And density of solution = 1.2 g/mL
Volume of solution = 100/1.2 = 83.33 mL = 0.08333 L
Moles of HCl will be calculated as:
n = W/M, where
W = given mass = 37g
M = molar mass = 36.4g/mol
n = 37/36.4 = 1.014mol
Then the molarity of the stock solution will be calculated as:
M = n/V
M = 1.014 / 0.0833 = 12.17M
Now the required volume of stock solution will be calculated by using the following equation as:
M₁V₁ = M₂V₂, where
M₁ & V₁ is the molarity and volume of stock solution and M₂ & V₂ is the molarity and volume of dilute solution. On putting values in the above solution we get
12.17 × V₁ = 0.5 × 2500
12.17 × V₁ = 1250
V₁ = 102.71 mL
Hence required volume of stock solution is 102.71 mL.
To know more about molarity, visit the below link:
https://brainly.com/question/22283918
#SPJ1
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.