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A piece of tin foil has a volume of 0.5345 mm3. If the piece measures 10.0 mm long and 1.25 cm wide, what is the thickness of the foil?

Sagot :

Answer:

Thickness of foil = 0.004mm

Explanation:

V= length x width x height (height can also be known as the thickness 't')

0.5345=10.0 x (1.25÷10) x t

t=0.5345/10.0 x 12.5

t=0.004276mm

t=0.004mm