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Sagot :
Answer:
a1 = (V2 - V1) / 1 s = 3.75 m/s^2
a2 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
a3 = (V2 - V1) / (t2 - t1) = (7.5 - 3.75) / 1 s = 3.75 m/s^2
A) a = (a1 + a2 + a3) / 3 = 3.75 m/s^2
v = a (t2 - t1)
B) after 1 sec v = 3.75 m / sec^2 * 1 sec = 3.75 m/s
after 2 sec v = v0 + a t = 3.75 m/s + 3.75 m/s^2 * 1 s = 7.5 m/s
C) The velocity increases proportionaly to the time
D) One factor depends on the variation of the acceleration due to gravity because of different positions of measurement (on earth)
A much larger factor is due to air resisance of the air on the falling object
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