Let's first move everything, the constants and variables to one side
[tex]x^2-2=2x[/tex] ⇒ [tex]x^2-2x-2=0[/tex]
The second form is in the general form of the quadratic equation:
⇒ [tex]ax^2+bx+c = 0[/tex]
To find the value of x, we can use the quadratic formula:
⇒ look at the diagram attached
[tex]x = \frac{-b-\sqrt{b^2-4ac} }{2a} =\frac{2-\sqrt{(-2)^2-4(1)(-2)} }{2*1} =\frac{2-\sqrt{4+8} }{2} =\frac{2-\sqrt{12} }{2} =\frac{2-2\sqrt{3}}{2} =1-\sqrt{3}[/tex]
[tex]x = \frac{-b+\sqrt{b^2-4ac} }{2a} =\frac{2+\sqrt{(-2)^2-4(1)(-2)} }{2*1} =\frac{2+\sqrt{4+8} }{2} =\frac{2+\sqrt{12} }{2} =\frac{2+2\sqrt{3}}{2} =1+\sqrt{3}[/tex]
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Answer
To answer the question, just answer in the order I solved it, because the question asks you to put the answer in ascending order which means from least to greatest.
Hope that helps!
